Hindawi Publishing Corporation Mathematical Problems in Engineering Volume 2010, Article ID 498249, 10 pages doi:10.1155/2010/498249 Research Article Exact Solutions for the Generalized BBM Equation with Variable Coef?cients Cesar A. G ? omez1 and Alvaro H. Salas2, 3 1 Department of Mathematics, Universidad Nacional de Colombia, Bogot? a, Colombia 2 Department of Mathematics and Statistics, Universidad Nacional de Colombia, Manizales, Cll 45, Cra 30, Colombia 3 Department of Mathematics, Universidad de Caldas, Manizales, Colombia Correspondence should be addressed to Alvaro H. Salas, asalash2002@yahoo.com Received 23 November 2009; Accepted 21 January 2010 Academic Editor: Jihuan He Copyright q 2010 C. A. G? omez and A. H. Salas. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. The variational iteration algorithm combined with the exp-function method is suggested to solve the generalized Benjamin-Bona-Mahony equation BBM with variable coe?cients. Periodic and soliton solutions are formally derived in a general form. Some particular cases are considered. 1. Introduction The BBM equation ut uux ux ? μuxxt 0, 1.1 which describes approximately the unidirectional propagation of long waves in certain nonlinear dispersive systems, has been proposed by Benjamin et al. in 1972 1 as a more satisfactory model than the KdV equation 2 ut uux uxxx 0. 1.2 It is easy to see that 1.1 can be derived from the equal width EW-equation 3 : ut uux ? μuxxt 0, 1.3 by means of the change of variable u u 1, that is, by replacing u with u 1. This last equation is considered as an equally valid and accurate model for the same wave phenomena 2 Mathematical Problems in Engineering simulated by 1.1 and 1.2 . On the other hand, some researches analyzed the generalized KdV equation with variable coe?cients ut σ t up ux μ t uxxx 0, 1.4 because this model has important applications in several ?elds of science 4–7 . Motivated by these facts, we will consider here the generalized EW-equation with variable coe?cients ut σ t up ux ? μ t uxxt 0. 1.5 Using the solutions of 1.5 we obtain exact solutions to the generalized BBM equation ut σ t u 1 p ux ? μ t uxxt 0, 1.6 of order p > 0. 2. Exact Solutions to Generalized BBM Equation 2.1. The Variational Iteration Method Consider the following nonlinear equation: Lu x, t Nu x, t g x, t , 2.1 where L and N are linear and nonlinear operators, respectively, and g x, t is an inhomogeneous term. According to the variational iteration method VIM 8–14 , a functional correction to 2.1 is given by un 1 x, t un x, t t 0 θ τ Lun x, τ Nun x, τ ? g x, τ dτ, 2.2 where θ τ is a general Lagrange's multiplier, which can be identi?ed via the variational theory; the subscript n ≥ 0 denotes the nth order approximation and u is a restricted variation which means δu 0. In this method, we ?rst determine the Lagrange multiplier θ τ that will be identi?ed optimally via integration by parts. The successive approximation un 1 of the solution u will be readily obtained upon using the determined Lagrangian multiplier and any selective function u0. One of the advantages of the VIM, is the free choice of the initial solution u0 x, t . If we consider a special form to u0 with arbitrary parameters, using the relations un x, t un 1 x, t , ?k ?tk un x, t ?k ?tk un 1 x, t , 2.3 Mathematical Problems in Engineering 3 we can obtain a set of algebraic equations in the unknowns given by the parameters that appear in u0. Solving this system, we have exact solutions to 2.1 . To solve 1.5 , we construct the following functional equation un 1 x, t un x, t t 0 θ τ Lun x, τ Nun x, τ dτ, 2.4 where Lun x, τ un τ x, τ , Nun x, τ σ τ u 1 p ux x, τ ? μ τ uxxτ x, τ . 2.5 Taking in 2.4 variation with respect to the independent variable un, and noticing that δNun 0 we have δun 1 x, t δun x, t δ t 0 θ τ Lun x, τ Nun x, τ dτ δun x, t θ t δun x, t ? t 0 θ τ δun x, τ dτ 0. 2.6 This yields the stationary conditions 1 θ t 0, θ t 0. 2.7 Therefore, θ t ?1. 2.8 Substituting this value into 2.4 we obtain the formula un 1 x, t un x, t ? t 0 Lun x, τ Nun x, τ dτ. 2.9 Using the wave transformation ξ x λt ξ0, 2.10 4 Mathematical Problems in Engineering setting ? ?t u1 ξ ? ?t u0 ξ , 2.11 and performing one integration, 2.9 reduces to λu0 ξ σ t p 1 u p 1 0 ξ ? λμ t u0 ξ 0, 2.12 where for sake of simplicity we set the constant of integration equal to zero. With the change of variable u0 ξ v2/p ξ , 2.13 equation 2.12 converts to λv2 ξ ? 2μ t 2 ? p p2 λ v 2 ? 2μ t p λv ξ v ξ σ t p 1 v ξ 4 0. 2.14 Observe that if v ξ is a solution to 2.14 , then ?v ξ is also a solution to this equation. 2.2. The Exp-Function Method Recently, He and Wu 15 have introduced the Exp-function method to solve nonlinear di?erential equations. In particular, the Exp-function method is an e?ective method for solving nonlinear equations with high nonlinearity. The method has been used in a satisfactory way by other authors to solve a great variety of nonlinear wave equations 15– 21 . The Exp-function method is very simple and straightforward, and can be brie?y revised as follows: Given the nonlinear partial di?erential equation F u, ux, ut, uxx, uxt, utt, . . . 0, 2.15 it is transformed to ordinary di?erential equation F u, u , u , u , uxt, . . . 0, 2.16 by mean of wave transformation ξ x λt ξ0. Solutions to 2.16 can then be found using the expression u ξ d n ?c an exp nξ q n ?p bn exp nξ , 2.17 Mathematical Problems in Engineering 5 where c, d, p, and q are positive integers which are unknown to be determined later, an and bn are unknown constants. After balancing, we substitute 2.17 into 2.16 to obtain an algebraic systems in the variable ζ exp nξ . Solving the algebraic system we can obtain exact solutions to 2.16 and reversing, solutions to 2.15 in the original variables. 3. Solutions to 2.14 by the Exp-Function Method Using the Exp-function method, we suppose that solutions to 2.14 can be expressed in the form v ξ 1 n ?1 an exp nrξ 1 m ?1 bm exp mrξ a?1 exp ?rξ a0 a1 exp rξ b?1 exp ?rξ b0 b1 exp rξ . 3.1 We obtain following solutions to 2.14 : v1 ± 2λk p 1 p 2 2 p 1 p 2 λ exp p/2 μ t ξ ? k2σ t exp ? p/2 μ t ξ , λ λ t , v2 ± 2λk p 1 p 2 σ t k2 exp p/2 μ t ξ ? 2λ p 1 p 2 exp ? p/2 μ t ξ , λ λ t . 3.2 Some special solutions are obtained if λ λ t ± k2 2 p2 3p 2 σ t . 3.3 This choice gives solutions v3 ± k 2 csch p 2 μ t ξ , λ k2 2 p2 3p 2 σ t , 3.4 v4 k 2 sech p 2 μ t ξ , λ ? k2 2 p2 3p 2 σ t , 3.5 v5 ± k 2 csc p 2 μ t ξ , λ ? k2 2 p2 3p 2 σ t . 3.6 6 Mathematical Problems in Engineering Solution 3.6 follows from 3.4 with the identi?cations μ t → ?μ t and k → ?k √ ?1. v6 ? k 2 sec p 2 μ t ξ , λ ? k2 2 p2 3p 2 σ t . 3.7 Solution 3.7 follows from 3.4 with the identi?cations μ t → ?μ t and k → ?k. 4. Particular Cases 4.1. Case 1: Solutions to 2.14 When p 2 Equation 2.14 takes the form λv2 ξ ? λμ t v ξ v ξ 1 3 σ t v ξ 4 0. 4.1 From 3.2 with p 2: v7 ± 24λk 24λ exp 1/ μ t ξ ? k2σ t exp ? 1/ μ t ξ , v8 ± 24λk k2σ t exp 1/ μ t ξ ? 24λ exp ? 1/ μ t ξ . 4.2 From 3.3 – 3.7 with p 2: v9 ± k 2 csch 1 μ t ξ , λ k2 24 σ t , v10 ± k 2 sech 1 μ t ξ , λ ? k2 24 σ t , v11 ± k 2 csc 1 ?μ t ξ , λ ? k2 24 σ t , v12 ± k 2 sec 1 μ t ξ , λ ? k2 24 σ t . 4.3 Mathematical Problems in Engineering 7 Other exact solutions are: v13 ± 3a2 exp 2 ?2/μ t ξ 2 √ 55a exp ?2/μ t ξ ? 22 k 3a2 exp 2 ?2/μ t ξ 22a exp ?2/μ t ξ 22 , λ ? 1 3 k2 σ t , v14 ± 3a2 ± 2 √ 55a exp ?2/μ t ξ ? 22 exp 2 ?2/μ t ξ k 3a2 22a exp ?2/μ t ξ 22 exp 2 ?2/μ t ξ , λ ? 1 3 k2 σ t , v15 ±k ? ? ?1 ? 44 8 √ 55 3a 11 √ 55 exp ?2/μ t ξ 22 8 √ 55 ? ? ?, λ ? 1 3 k2 σ t , v16 ± k a ± sinh ?2/μ t ξ √ a2 1 ± cosh ?2/μ t ξ , λ ? 1 3 k2 σ t , v17 ± k a ± cosh ?2/μ t ξ √ a2 1 ± sinh ?2/μ t ξ , λ ? 1 3 k2 σ t , v18 ± k cos 2/μ t ξ 1 ± sin 2/μ t ξ , λ k2 3 σ t . 4.4 4.2. Case 2: Solutions to 2.14 When p 4 Equation 2.14 takes the form λv2 ξ μ t λ v 2 ? λ 2 μ t v ξ v ξ 1 5 σ t v ξ 4 0. 4.5 From 3.2 with p 4: v19 ± 60λk 60λ exp 2/ μ t ξ ? k2σ t exp ? 2/ μ t ξ , λ λ t , v20 ± 60λk σ t k2 exp 2/ μ t ξ ? 60λ exp ? 2/ μ t ξ , λ λ t . 4.6 8 Mathematical Problems in Engineering From 3.3 – 3.7 with p 4: v21 ± k 2 csch 2 μ t ξ , λ k2 60 σ t , v22 ± k 2 sech 2 μ t ξ , λ ? k2 60 σ t , v23 ± k 2 csc 2 ?μ t ξ , λ ? k2 60 σ t , v24 ± k 2 sec 2 ?μ t ξ , λ ? k2 60 σ t . 4.7 Other exact solutions are: v25 ± k a exp 2/ ?μ t ξ ? 4 2 a2 exp 4/ ?μ t ξ 16a exp 2/ ?μ t ξ 16 , λ ? 1 5 k2 σ t , v26 ± k 4 exp 2/ ?μ t ξ ? a 2 a2 16a exp 2/ ?μ t ξ 16 exp 4/ ?μ t ξ , λ ? 1 5 k2 σ t , v27 ±2k ? ? ?1 ? 3 2 ± cos 2/ μ t ξ ? ? ?, λ ? 4 5 k2 σ t , v28 ±2k ? ? ?1 ? 3 2 ± sin 2/ μ t ξ ? ? ?, λ ? 4 5 k2 σ t . 4.8 It is clear that using 2.13 we obtain solutions to 1.5 . Finally, observe that if u0 x, t is a solution of 1.5 , then the solutions u x, t to the generalized BBM equation 1.6 are obtained as follows: u x, t u0 x, t ? 1. 4.9 5. Conclusions We have considered the generalized EW-equation with variable coe?cients and the generalized BBM-equation with variable coe?cients. We obtained analytic solutions by using the variational iteration method combined with the exp-function method. With the aid of Mathematica we have derived a lot of di?erent types of solutions for these two models. Combined formal soliton-like solutions as well as kink solutions have been formally derived. Mathematical Problems in Engineering 9 The results obtained show that the technique used here can be considered as a powerful method to analyze other types of nonlinear wave equations. According to 22 , there are alternative iteration alorithms, which might be useful for future work. 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